B = 5C
Y1 = A + B
Y2 = A B
Y3 = A . B
JAWAB:
A = 3F
= 3x161 + F(15)x 160
= 48 + 15
= 6310 = 1 1 1 1 1 12
B= 5C
= 5x161 + C(12)x160
=80 + 12
= 9210 = 1 0 1 1 1 0 02
A | B | Y1 = A + B | Y2 = A B | Y3 = A . B |
0 | 1 | 1 | 1 | 0 |
1 | 0 | 1 | 1 | 0 |
1 | 1 | 1 | 0 | 1 |
1 | 1 | 1 | 0 | 1 |
1 | 1 | 1 | 0 | 1 |
1 | 0 | 1 | 1 | 0 |
1 | 0 | 1 | 1 | 0 |
Y1=1x26+1x25+1x24+1x23+1x22+1x21+1x20
=64 + 32 + 16 + 8 + 4 + 2 +1
=12710 = 7F16
Y2 = 1x26+1x25+0x24+0x23+0x22+1x21+1x20
= 64 + 32 +0 +0 +0 +2+ 1
=9910 = 6316
Y3= 0x26+0x25+1x24+1x23+1x22+0x21+0x20
= 0+0+16+8+4+0+0
=2810 =1C16
2. 2.A= 3C
B = 5F
X1=A+B
X2=A – B
JAWAB:
A= 3x161+C(12)x160
= 48 +12
=6010 = 1 1 1 1 0 02
B=5x161+F(15)x160
=80 +15
=9510 = 10111112
X1=A + B
A = 0 1 1 1 1 0 0
B = 1 0 1 1 1 1 1 +
S = 1 0 0 1 1 0 1 12
= 15510
= 9B16
X2 =A – B
B’ = 0 1 0 0 0 0 0
1 +
= 0 1 0 0 0 0 1
A = 0 1 1 1 1 0 0
B’= 0 1 0 0 0 0 1 +
S = 1 0 1 1 1 0 1
3. A = 516 = 5 x 16 = 8010 = 1 0 1 0 0 0 02
B = 616 = 6 x 16 = 9610 = 1 1 0 0 0 0 02
C = 716 = 7 x 16 = 11210 =1 1 1 0 0 0 02
D = 816 = 8 x 16 = 12810 =1 0 0 0 0 0 0 02
A | B | C | D | Q |
0 | 0 | 0 | 1 | 0 |
1 | 1 | 1 | 0 | 0 |
0 | 1 | 1 | 0 | 0 |
1 | 0 | 1 | 0 | 0 |
0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | 0 |
Q = A’B’C’D + ABCD’ + A’BCD’ + AB’CD’ + A’B’C’D’
= A’B’C’(D+D’) + BCD’(A+A’) +AB’CD’
= A’B’C’+BCD’ +AB’CD’